Determine the limit L=limn→∞∫01nsin(x)n+xdxL = \lim_{n \to \infty} \int_{0}^{1} \frac{n \sin(x)}{n+x} dxL=limn→∞∫01n+xnsin(x)dx.
L=1−cos(1)L = 1 - \cos(1)L=1−cos(1)
L=sin(1)L = \sin(1)L=sin(1)
L=1L = 1L=1
L=0L = 0L=0