Determine the inverse of f(x)=x−53+2f(x) = \sqrt[3]{x-5} + 2f(x)=3x−5+2.
f−1(x)=(x−2)3+5f^{-1}(x) = (x-2)^3 + 5f−1(x)=(x−2)3+5
f−1(x)=(x+2)3−5f^{-1}(x) = (x+2)^3 - 5f−1(x)=(x+2)3−5
f−1(x)=(x−5)3+2f^{-1}(x) = (x-5)^3 + 2f−1(x)=(x−5)3+2
f−1(x)=x3−7f^{-1}(x) = x^3 - 7f−1(x)=x3−7