Determine the inverse of f(x)=2x−1+3f(x) = 2^{x-1} + 3f(x)=2x−1+3.
f−1(x)=log2(x−3)+1f^{-1}(x) = \log_2(x-3) + 1f−1(x)=log2(x−3)+1
f−1(x)=log2(x+3)−1f^{-1}(x) = \log_2(x+3) - 1f−1(x)=log2(x+3)−1
f−1(x)=2x+3−1f^{-1}(x) = 2^{x+3} - 1f−1(x)=2x+3−1
f−1(x)=12x−3+1f^{-1}(x) = \frac{1}{2^{x-3}} + 1f−1(x)=2x−31+1