Determine the interval of convergence for the power series: ∑n=1∞(n!)2(2n)!xn\sum_{n=1}^{\infty} \frac{(n!)^2}{(2n)!} x^n∑n=1∞(2n)!(n!)2xn
(−4,4)(-4, 4)(−4,4)
[−4,4][-4, 4][−4,4]
(−4,4](-4, 4](−4,4]
[−4,4)[-4, 4)[−4,4)