Determine the image of the circle x2+y2=1x^2 + y^2 = 1x2+y2=1 in the line x+y=2x + y = 2x+y=2.
(x−2)2+(y−2)2=1(x-2)^2 + (y-2)^2 = 1(x−2)2+(y−2)2=1
x2+y2=1x^2 + y^2 = 1x2+y2=1
(x−1)2+(y−1)2=1(x-1)^2 + (y-1)^2 = 1(x−1)2+(y−1)2=1
(x+1)2+(y+1)2=1(x+1)^2 + (y+1)^2 = 1(x+1)2+(y+1)2=1