Determine the general solution of y′=ylnyxy' = \frac{y \ln y}{x}y′=xylny.
lny=Cx\ln y = Cxlny=Cx
y=eCxy = e^{Cx}y=eCx
y=Cxy = Cxy=Cx
lny=C+x2\ln y = C + x^2lny=C+x2