Determine the general solution of y′=x2yy' = \frac{x^2}{y}y′=yx2.
y2=x3+Cy^2 = x^3 + Cy2=x3+C
y2=23x3+Cy^2 = \frac{2}{3} x^3 + Cy2=32x3+C
y=13x3+Cy = \frac{1}{3} x^3 + Cy=31x3+C
y2=13x3+Cy^2 = \frac{1}{3} x^3 + Cy2=31x3+C