Determine the general solution of the differential equation y′=y2y' = y^2y′=y2.
y=−1x+Cy = \frac{-1}{x + C}y=x+C−1
y=1x+Cy = \frac{1}{x} + Cy=x1+C
y=ex2+Cy = e^{x^2} + Cy=ex2+C
y=1C−xy = \frac{1}{C - x}y=C−x1