Determine the general solution of the differential equation dydx=ex\frac{dy}{dx} = e^xdxdy=ex.
y=ex+Cy = e^x + Cy=ex+C
y=ex+1+Cy = e^{x+1} + Cy=ex+1+C
y=xex+Cy = x e^x + Cy=xex+C
y=1xex+Cy = \frac{1}{x} e^x + Cy=x1ex+C