Determine the general solution of the differential equation y′+6xy=x2y' + \frac{6}{x}y = x^2y′+x6y=x2.
y=x39+Cx−6y = \frac{x^3}{9} + Cx^{-6}y=9x3+Cx−6
y=x36+Cx−6y = \frac{x^3}{6} + Cx^{-6}y=6x3+Cx−6
y=x69+Cx−6y = \frac{x^6}{9} + Cx^{-6}y=9x6+Cx−6
y=x29+Cx−6y = \frac{x^2}{9} + Cx^{-6}y=9x2+Cx−6