Determine the general solution for y′=yx+1y' = \frac{y}{x} + 1y′=xy+1.
y=xln∣x∣+Cxy = x \ln|x| + Cxy=xln∣x∣+Cx
y=ln∣x∣+Cy = \ln|x| + Cy=ln∣x∣+C
y=x2+Cxy = x^2 + Cxy=x2+Cx
y=xln∣x∣+Cy = x \ln|x| + Cy=xln∣x∣+C