Determine the general solution for y′+2y=4e−2xy' + 2y = 4e^{-2x}y′+2y=4e−2x.
y=(4x+C)e−2xy = (4x + C)e^{-2x}y=(4x+C)e−2x
y=4xe−2x+Cy = 4x e^{-2x} + Cy=4xe−2x+C
y=4e−2x+Cy = 4e^{-2x} + Cy=4e−2x+C
y=(4x+C)e2xy = (4x + C)e^{2x}y=(4x+C)e2x