Determine the derivative of f(t)=9t23f(t) = 9\sqrt[3]{t^2}f(t)=93t2.
6t−1/36t^{-1/3}6t−1/3
3t2/33t^{2/3}3t2/3
18t1/318t^{1/3}18t1/3
6t1/36t^{1/3}6t1/3