Determine the convergence of ∑n=1∞1n3\sum_{n=1}^{\infty} \frac{1}{\sqrt{n^3}}∑n=1∞n31.
Converges as p-series (p=3/2>1p=3/2 > 1p=3/2>1)
Diverges as p-series (p=1/2<1p=1/2 < 1p=1/2<1)
Converges as geometric series
Diverges as geometric series