Determine the behavior of L=limx→0ln(1+x)−xxsinxL = \lim_{x \to 0} \frac{\ln(1+x) - x}{x \sin x}L=limx→0xsinxln(1+x)−x.
L=1L = 1L=1
L=−1L = -1L=−1
L=−1/2L = -1/2L=−1/2
L=0L = 0L=0