Determine the area of the region bounded by the ellipse 4x2+9y2=364x^2 + 9y^2 = 364x2+9y2=36 and the line y=1y = 1y=1.
6π−456\pi - 4\sqrt{5}6π−45
3π−253\pi - 2\sqrt{5}3π−25
6π−85/36\pi - 8\sqrt{5}/36π−85/3
4π−54\pi - \sqrt{5}4π−5