Determine ∫xx+1dx\int x \sqrt{x+1} dx∫xx+1dx.
25(x+1)5/2−23(x+1)3/2+C\frac{2}{5}(x+1)^{5/2} - \frac{2}{3}(x+1)^{3/2} + C52(x+1)5/2−32(x+1)3/2+C
25(x+1)5/2+23(x+1)3/2+C\frac{2}{5}(x+1)^{5/2} + \frac{2}{3}(x+1)^{3/2} + C52(x+1)5/2+32(x+1)3/2+C
23(x+1)3/2−25(x+1)5/2+C\frac{2}{3}(x+1)^{3/2} - \frac{2}{5}(x+1)^{5/2} + C32(x+1)3/2−52(x+1)5/2+C
x(x+1)3/2+Cx(x+1)^{3/2} + Cx(x+1)3/2+C