Determine if ∑n=1∞13n\sum_{n=1}^{\infty} \frac{1}{3^n}∑n=1∞3n1 converges.
Converges because it is a geometric series with ∣r∣<1|r| < 1∣r∣<1.
Diverges because the terms approach 0.
Converges because it is a ppp-series.
Diverges because r>1r > 1r>1.