Convert 3+3i3 + 3i3+3i to polar form and identify the argument.
r=32,θ=π/4r = 3\sqrt{2}, \theta = \pi/4r=32,θ=π/4
r=6,θ=π/4r = 6, \theta = \pi/4r=6,θ=π/4
r=3,θ=π/4r = 3, \theta = \pi/4r=3,θ=π/4
r=32,θ=π/2r = 3\sqrt{2}, \theta = \pi/2r=32,θ=π/2