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Matricesmedium
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Consider the Schur complement: for a block matrix with AAA invertible, the Schur complement S=D−CA−1BS = D - CA^{-1}BS=D−CA−1B relates to the full block matrix determinant by: det⁡(ABCD)=?\det\begin{pmatrix} A & B \\ C & D \end{pmatrix} = ?det(AC​BD​)=?