Consider the recurrence relation an=3an−1−2an−2a_n = 3a_{n-1} - 2a_{n-2}an=3an−1−2an−2 with a0=1a_0 = 1a0=1 and a1=2a_1 = 2a1=2. What is a4a_4a4?
a4=14a_4 = 14a4=14
a4=20a_4 = 20a4=20
a4=26a_4 = 26a4=26
a4=32a_4 = 32a4=32