Consider the recurrence an=an−1⋅an−2a_n = a_{n-1} \cdot a_{n-2}an=an−1⋅an−2. With a0=2,a1=4a_0 = 2, a_1 = 4a0=2,a1=4, what is a3a_3a3?
32
64
128
16