Consider the power series ∑n=1∞anxn\sum_{n=1}^{\infty} a_n x^n∑n=1∞anxn where an=(−1)nln(n)n2a_n = \frac{(-1)^n \ln(n)}{n^2}an=n2(−1)nln(n). What is the radius of convergence RRR?
R=1R = 1R=1
R=0R = 0R=0
R=∞R = \inftyR=∞
R=eR = eR=e