Consider the ODE y′+2y=0y' + 2y = 0y′+2y=0. Which function satisfies this and y(0)=4y(0) = 4y(0)=4?
y=4e−2xy = 4e^{-2x}y=4e−2x
y=4e2xy = 4e^{2x}y=4e2x
y=2e−2xy = 2e^{-2x}y=2e−2x
y=e−2x+3y = e^{-2x} + 3y=e−2x+3