Determinantshard
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Consider the matrix A=(1234567810)A = \begin{pmatrix} 1 & 2 & 3 \\ 4 & 5 & 6 \\ 7 & 8 & 10 \end{pmatrix}. Using the property det(A)=det(AλI)+\det(A) = \det(A - \lambda I) + \dots or row operations, compute det(A)\det(A).