Consider the integral I=∫01x2−xln(x)dxI = \int_0^1 \frac{x^2 - x}{\ln(x)} dxI=∫01ln(x)x2−xdx. Which of the following evaluations is correct?
ln(3/2)\ln(3/2)ln(3/2)
ln(2/3)\ln(2/3)ln(2/3)
ln(4/3)\ln(4/3)ln(4/3)
ln(3/4)\ln(3/4)ln(3/4)