Consider the inner product ⟨u,v⟩=u1v1+2u2v2\langle u, v \rangle = u_1 v_1 + 2 u_2 v_2⟨u,v⟩=u1v1+2u2v2 in R2\mathbb{R}^2R2. Find ∥u∥\|u\|∥u∥ for u=(1,1)u = (1, 1)u=(1,1).
2\sqrt{2}2
3\sqrt{3}3
2
333