Consider the function g(x)=∫0x2e−t2dtg(x) = \int_0^{x^2} e^{-t^2} dtg(x)=∫0x2e−t2dt. What is g′′(x)g''(x)g′′(x)?
2e−x42e^{-x^4}2e−x4
2e−x4−4x2e−x42e^{-x^4} - 4x^2e^{-x^4}2e−x4−4x2e−x4
4xe−x44x e^{-x^4}4xe−x4
4xe−x4−8x3e−x44x e^{-x^4} - 8x^3 e^{-x^4}4xe−x4−8x3e−x4