Consider the function f(x)=∑n=0∞x2n+1(2n+1)!⋅3nf(x) = \sum_{n=0}^{\infty} \frac{x^{2n+1}}{(2n+1)! \cdot 3^n}f(x)=∑n=0∞(2n+1)!⋅3nx2n+1. What is the value of f′′(0)f''(0)f′′(0)?
0
1
1/3
2/3