Exponentials & Logarithmshard
0:00.0

Consider the function f(x)=loga(x2bx+c)f(x) = \log_{a}(x^2 - bx + c). If the vertical asymptotes are at x=1x = 1 and x=5x = 5, and the function satisfies f(3)=0f(3) = 0, what is the value of a+b+ca + b + c assuming a>1a > 1 and the base is such that f(6)=1f(6) = 1?