Consider the equation dydt+2y=4t\frac{dy}{dt} + 2y = 4tdtdy+2y=4t. What is the general solution?
y=Ce−2t+2t−1y = Ce^{-2t} + 2t - 1y=Ce−2t+2t−1
y=Ce−2t+2t+1y = Ce^{-2t} + 2t + 1y=Ce−2t+2t+1
y=Ce2t+2t−1y = Ce^{2t} + 2t - 1y=Ce2t+2t−1
y=Ce−2t+t−1y = Ce^{-2t} + t - 1y=Ce−2t+t−1