Consider f(x)=x2sin(x)f(x) = x^2 \sin(x)f(x)=x2sin(x). What is the second derivative f′′(x)f''(x)f′′(x)?
(2−x2)sin(x)+4xcos(x)(2-x^2) \sin(x) + 4x \cos(x)(2−x2)sin(x)+4xcos(x)
2sin(x)+2xcos(x)2 \sin(x) + 2x \cos(x)2sin(x)+2xcos(x)
x2sin(x)+4xcos(x)+2sin(x)x^2 \sin(x) + 4x \cos(x) + 2 \sin(x)x2sin(x)+4xcos(x)+2sin(x)
2xcos(x)−x2sin(x)2x \cos(x) - x^2 \sin(x)2xcos(x)−x2sin(x)