Consider f(x)=x2sin(1x)f(x) = x^2 \sin(\frac{1}{x})f(x)=x2sin(x1) for x≠0x \neq 0x=0 and f(0)=0f(0) = 0f(0)=0. Which of the following is true?
The function is discontinuous at x=0x=0x=0
limx→0f(x)=0\lim_{x \to 0} f(x) = 0limx→0f(x)=0
The Squeeze Theorem cannot be applied
The limit does not exist