Consider f(x)=x2f(x) = x^2f(x)=x2 and g(x)=x+3g(x) = x + 3g(x)=x+3. Which calculation correctly finds (f∘g)(1)(f \circ g)(1)(f∘g)(1)?
f(1)+g(1)=1+4=5f(1) + g(1) = 1 + 4 = 5f(1)+g(1)=1+4=5
g(f(1))=g(1)=4g(f(1)) = g(1) = 4g(f(1))=g(1)=4
f(g(1))=f(4)=16f(g(1)) = f(4) = 16f(g(1))=f(4)=16
f(1)⋅g(1)=1⋅4=4f(1) \cdot g(1) = 1 \cdot 4 = 4f(1)⋅g(1)=1⋅4=4