Consider dydx=x+3\frac{dy}{dx} = x + 3dxdy=x+3. Which specific solution satisfies y(0)=5y(0) = 5y(0)=5?
y=x2+3x+5y = x^2 + 3x + 5y=x2+3x+5
y=12x2+3x+5y = \frac{1}{2}x^2 + 3x + 5y=21x2+3x+5
y=12x2+5y = \frac{1}{2}x^2 + 5y=21x2+5
y=x+5y = x + 5y=x+5