Consider dudt=−2u\frac{du}{dt} = -2udtdu=−2u. If u(0)=10u(0) = 10u(0)=10, what is u(t)u(t)u(t)?
u(t)=10+e−2tu(t) = 10 + e^{-2t}u(t)=10+e−2t
u(t)=10e−2tu(t) = 10e^{-2t}u(t)=10e−2t
u(t)=10e2tu(t) = 10e^{2t}u(t)=10e2t
u(t)=5e−2tu(t) = 5e^{-2t}u(t)=5e−2t