Ononot — Consider an = 4a{n-1} - 4a{n-2} with a0 = 1 and a1 = 4. The

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Recurrence Relationseasy

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Consider $a_n = 4a_{n-1} - 4a_{n-2}$ with $a_0 = 1$ and $a_1 = 4$ . The general solution is $a_n = (c_1 + c_2 n) \cdot 2^n$ . What is $c_1$ ?