Compute 3⋅(2−104)3 \cdot \begin{pmatrix} 2 & -1 \\ 0 & 4 \end{pmatrix}3⋅(20−14).
(6−3012)\begin{pmatrix} 6 & -3 \\ 0 & 12 \end{pmatrix}(60−312)
(2−104)\begin{pmatrix} 2 & -1 \\ 0 & 4 \end{pmatrix}(20−14)
(63012)\begin{pmatrix} 6 & 3 \\ 0 & 12 \end{pmatrix}(60312)
(5237)\begin{pmatrix} 5 & 2 \\ 3 & 7 \end{pmatrix}(5327)