Multivariable & Vectorhard
0:00.0

Calculate the surface area of the part of the surface z=23(x3/2+y3/2)z = \frac{2}{3}(x^{3/2} + y^{3/2}) that lies above the square region D={(x,y)0x1,0y1}D = \{(x, y) \mid 0 \le x \le 1, 0 \le y \le 1\}.