Calculate the derivative of f(x)=2xx3f(x) = \frac{2^x}{x^3}f(x)=x32x.
2x(xln2−3)x4\frac{2^x(x \ln 2 - 3)}{x^4}x42x(xln2−3)
2x(xln2−3)x6\frac{2^x(x \ln 2 - 3)}{x^6}x62x(xln2−3)
x3⋅2xln2−3x2⋅2xx6\frac{x^3 \cdot 2^x \ln 2 - 3x^2 \cdot 2^x}{x^6}x6x3⋅2xln2−3x2⋅2x
2xln23x2\frac{2^x \ln 2}{3x^2}3x22xln2