Calculate ∫0π/2cos(θ)1+sin2(θ)dθ\int_{0}^{\pi/2} \frac{\cos(\theta)}{1+\sin^2(\theta)} d\theta∫0π/21+sin2(θ)cos(θ)dθ.
π/4\pi/4π/4
π/2\pi/2π/2
111
ln(2)\ln(2)ln(2)