Ononot — By the rank-nullity theorem, for an m \times n matrix A: \te

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By the rank-nullity theorem, for an $m \times n$ matrix $A$ : $\text{rank}(A) + \text{nullity}(A) = n$ where nullity is the dimension of the null space $\ker(A)$ . For a $6 \times 4$ matrix $A$ with rank 2, what is the dimension of the null space?