At what points do the parabola y=x2−3x+2y = x^2 - 3x + 2y=x2−3x+2 and the line y=2y = 2y=2 intersect?
(1,2)(1, 2)(1,2) and (2,2)(2, 2)(2,2)
(0,2)(0, 2)(0,2) and (3,2)(3, 2)(3,2)
(−1,2)(-1, 2)(−1,2) and (4,2)(4, 2)(4,2)
No intersection