Apply the Limit Comparison Test to ∑n=1∞n2+3n2n4−n2+1\sum_{n=1}^{\infty} \frac{n^2 + 3n}{2n^4 - n^2 + 1}∑n=1∞2n4−n2+1n2+3n by comparing with bn=1n2b_n = \frac{1}{n^2}bn=n21. What is limn→∞anbn\lim_{n \to \infty} \frac{a_n}{b_n}limn→∞bnan?
lim=0\lim = 0lim=0
lim=12\lim = \frac{1}{2}lim=21
lim=∞\lim = \inftylim=∞
The limit does not exist