Real-World Applicationshard
0:00.0

An industrial filter's throughput T(t)T(t) is modeled by the differential equation dTdt+0.1T=5e0.05t\frac{dT}{dt} + 0.1T = 5e^{-0.05t}. If T(0)=0T(0) = 0, what is the throughput at t=10t=10?