Add: xx2−4+2x2−4\dfrac{x}{x^2 - 4} + \dfrac{2}{x^2 - 4}x2−4x+x2−42.
1x−2\dfrac{1}{x - 2}x−21
x+2x2−4\dfrac{x+2}{x^2-4}x2−4x+2
x+2(x−2)(x+2)\dfrac{x+2}{(x-2)(x+2)}(x−2)(x+2)x+2
1x+2\dfrac{1}{x+2}x+21