A satellite orbits the Earth in a circular path. The orbital velocity is given by $v = \sqrt{\frac{G M}{R + h}}$, where the constant $G M = 3.6 \times 10^{14}\text{ m}^3/\text{s}^2$, the Earth's radius is $R = 6.4 \times 10^6$ meters, and $h$ is the satellite's altitude. If a satellite orbits at an altitude of $3.6 \times 10^6$ meters, what is its velocity in meters per second?