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Recursionhard
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A recurrence T(n)=3T(n/4)+nlog⁡2nT(n) = 3T(n/4) + n\log_2 nT(n)=3T(n/4)+nlog2​n arises from a divide-and-conquer algorithm. Using the Master Theorem with a=3,b=4,f(n)=nlog⁡2na = 3, b = 4, f(n) = n\log_2 na=3,b=4,f(n)=nlog2​n, note that nlog⁡43≈n0.792n^{\log_4 3} \approx n^{0.792}nlog4​3≈n0.792. What is Θ(T(n))\Theta(T(n))Θ(T(n))?