Recursionmedium
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A recurrence relation is given by an=5an16an2a_n = 5a_{n-1} - 6a_{n-2}. If the general solution is an=c1(2n)+c2(3n)a_n = c_1(2^n) + c_2(3^n), what are the constants c1c_1 and c2c_2 given a0=1a_0 = 1 and a1=4a_1 = 4?