Recursionhard
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A recurrence relation arises from a divide-and-conquer algorithm: an=2an/2+1a_n = \sqrt{2} \cdot a_{n/2} + 1 (taking the square root of the number of subproblems). To solve, substitute bn=log2anb_n = \log_2 a_n to linearize. What is the growth rate Θ(an)\Theta(a_n)?